The 9 rectangles A, B, C, D, E, F, G, H and I overlap each other. Rectangle A intersects rectangles D and F; this relation could be written in shorthand as A(D, F). Moreover,
B(F, G)
C(G, H)
D(A, H)
E(H, I)
F(A, B, I)
G(B, C, I)
H(C, D, E)
I(E, F, G)
Label the rectangles appropriately with the letters A to I.
Solely the 4 blue-shaded rectangles under intersect three different rectangles, and subsequently they should be F, G, H and I. H doesn’t intersect F, G or I, whereas I intersects each F and G. Consequently, H is the topmost blue-shaded rectangle, and I is the third from the highest. As a result of B(F, G) and E(H, I), the 2 rectangles B and E additionally could be recognized. The remaining is easy.
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This puzzle initially appeared in Spektrum der Wissenschaft and was reproduced with permission.
